Domain of a Square Root Function
The domain of a square root function given by y = k √x is determined by the following:
- Range is a real number. The range is ≥ 0 when k ≥ 0, and the range is < 0 when k < 0.
- The domain is x ≥ 0.
Find the domain and range of the following function
- y =
As stated above, the linear function in a square root should always have its value greater than or equal to zero.
Therefore, the domain of y will be given by x – 1 ≥ 0 or x ≥ 1.
For the range of y, the value of the square root function will always be greater than or equal to zero.
Hence the range of y is ≥ 0.
- y =
Domain: x ≥ 0
For the range: since
≥ 0, y ≥ 0 + 5 or y ≥ 5.
- y =
To find the domain, we use the condition that 20-9x ≥0.
Add 9x on both sides: 20 ≥ 9x.
Divide both sides with 9: 20/9 ≥ x.
Hence the domain of y is x ≤ 20/9.
The range will be the same as for
because the square root function will always give a value ≥ 0.
Try this problem
- Find the domain of
- x > 9/5
- x < 9/5
- x ≥ 9/5
- x ≤ 9/5
The given square root function is
The square root function is defined for f(x)≥0.
Hence, f(x)= 5x-9>=0.
Add 9 to both the sides: 5x ≥9.
Divide by 9:
x ≥ 9/5